A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is $$0.02866\,u.$$ The energy liberated per $$u$$ is
(given $$1\,u = 931\,MeV$$ )
A.
$$2.67\,MeV$$
B.
$$26.7\,MeV$$
C.
$$6.675\,MeV$$
D.
$$13.35\,MeV$$
Answer :
$$6.675\,MeV$$
Solution :
Given, $$\Delta m = 0.02866\,u$$
∴ Energy liberated $$ = \Delta m{c^2}$$
⇒ Energy liberated per $$u = \frac{{0.02866 \times 931}}{4} = \frac{{26.7}}{4}MeV$$
$$\eqalign{
& = \frac{{{E_b}}}{A} \cr
& = 6.675\,MeV \cr} $$
Releted MCQ Question on Modern Physics >> Atoms or Nuclear Fission and Fusion
In the nuclear fusion reaction
$$_1^2H + _1^3H \to _2^4He + n$$
given that the repulsive potential energy between the two
nuclei is $$ \sim 7.7 \times {10^{ - 14}}J,$$ the temperature at which the gases must be heated to initiate the reaction is nearly
[Boltzmann’s Constant $$k = 1.38 \times {10^{ - 23}}J/K$$ ]
The binding energy per nucleon of deuteron $$\left( {_1^2H} \right)$$ and helium nucleus $$\left( {_2^4He} \right)$$ is $$1.1\,MeV$$ and $$7\,MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is