A bus is moving with a velocity of $$10\,m{s^{ - 1}}$$ on a straight road. A scootorist wishes to overtake the bus in one minute. If the bus is at a distance of $$1.2\,km$$ ahead, then the velocity with which he has to chase the bus is
A.
$$20\,m{s^{ - 1}}$$
B.
$$25\,m{s^{ - 1}}$$
C.
$$60\,m{s^{ - 1}}$$
D.
$$30\,m{s^{ - 1}}$$
Answer :
$$30\,m{s^{ - 1}}$$
Solution :
peed to cover $$1200\,m$$ by scootarist $${v_r} \times 60 = 1200 \Rightarrow {v_r} = 20$$
speed to overtake bus $$v = {v_r} + 10 = 30\,m/s$$
Releted MCQ Question on Basic Physics >> Kinematics
Releted Question 1
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