A body is projected from the ground with a velocity $$50\,m/s$$ at an angle of $${30^ \circ }.$$ It crosses a wall after $$3\,\sec .$$ How far beyond the wall the stone will strike the ground?
[take $$g = 10\,m/{s^2}$$ ]
A.
$$50\sqrt 3 $$
B.
$$70\sqrt 2 $$
C.
$$15\sqrt 3 $$
D.
$$16\sqrt 2 $$
Answer :
$$50\sqrt 3 $$
Solution :
Required distance from the wall $$ = \frac{{{u^2}\sin 2\theta }}{g} - u\cos \theta \times t = 50\sqrt 3 \,m$$
Releted MCQ Question on Basic Physics >> Kinematics
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