Question

A binary liquid solution is prepared by mixing $$n-$$heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution?

A. The solution is non-ideal, showing $$- ve$$  deviation from Raoult’s Law.
B. The solution is non-ideal, showing $$+ ve$$  deviation from Raoult’s Law.  
C. $$n-$$heptane shows $$+ ve$$  deviation while ethanol shows -ve deviation from Raoult’s Law.
D. The solution formed is an ideal solution
Answer :   The solution is non-ideal, showing $$+ ve$$  deviation from Raoult’s Law.
Solution :
For this solution intermolecular interactions between $$n$$ - heptane and ethanol are weaker than $$n$$ - heptane - $$n$$ - heptane & ethanol-ethanol interactions hence the solution of $$n$$ - heptane and ethanol is non-ideal and shows positive deviation from Raoult’s law.

Releted MCQ Question on
Physical Chemistry >> Solutions

Releted Question 1

An azeotropic solution of two liquids has boiling point lower than either of them when it

A. shows negative deviation from Raoult’s law
B. shows no deviation from Raoult’s law
C. shows positive deviation from Raoult’s law
D. is saturated
Releted Question 2

For a dilute solution, Raoult’s law states that :

A. the lowering of vapour pressure is equal to the mole fraction of solute.
B. the relative lowering of vapour pressure is equal to the mole fraction of solute.
C. the relative lowering of vapour pressure is proportional to the amount of solute in solution.
D. the vapour pressure of the solution is equal to the mole fraction of solvent.
Releted Question 3

When mercuric iodide is added to the aqueous solution of potassium iodide then

A. freezing point is raised.
B. freezing point is lowered.
C. freezing point does not change.
D. boiling point does not change.
Releted Question 4

Which of the following $$0.1 M$$  aqueous solutions will have the lowest freezing point?

A. Potassium sulphate
B. Sodium chloride
C. Urea
D. Glucose

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