A beam of light of wave length $$600\,nm$$ from a distance source falls on a single slit $$1mm$$ wide and a resulting diffraction pattern is observed on a screen $$2\,m$$ away. The distance between the first dark fringes on either side of central bright fringe is
A.
$$1.2\,cm$$
B.
$$1.2\,mm$$
C.
$$2.4\,cm$$
D.
$$2.4\,mm$$
Answer :
$$2.4\,mm$$
Solution :
The distance between the first dark fringe on either
side of the central maximum = width of central maximum
$$\eqalign{
& = \frac{{2\,D\lambda }}{a} \cr
& = \frac{{2 \times 2 \times 600 \times {{10}^{ - 9}}}}{{{{10}^{ - 3}}}} \cr
& = 2.4 \times {10^{ - 3}}m \cr
& = 2.4\,mm \cr} $$
Releted MCQ Question on Optics and Wave >> Wave Optics
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