A ball of mass $$10\,g$$ moving perpendicular to the plane of the wall strikes it and rebounds in the same line with the same velocity. If the impulse experienced by the wall is $$0.54\,Ns,$$ the velocity of the ball is
A.
$$27\,m{s^{ - 1}}$$
B.
$$3.7\,m{s^{ - 1}}$$
C.
$$54\,m{s^{ - 1}}$$
D.
$$37\,m{s^{ - 1}}$$
Answer :
$$27\,m{s^{ - 1}}$$
Solution :
As the ball, $$m = 10\,g = 0.01\,kg$$ rebounds after striking the wall
$$\therefore $$ Change in momentum $$ = mv - \left( { - mv} \right) = 2\,mv$$
Impulse = Change in momentum $$= 2mv$$
$$\therefore v = \frac{{{\text{Impulse}}}}{{2m}} = \frac{{0.54\,Ns}}{{2 \times 0.01\,kg}} = 27\,m{s^{ - 1}}$$
Releted MCQ Question on Basic Physics >> Impulse
Releted Question 1
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