Question
A 3 : 2 molar mixture of $${N_2}$$ and $$CO$$ is present in a vessel at $$500\,bar$$ pressure. Due to hole in the vessel, the gas mixture leaks out. The composition of mixture effusing out initially is
A.
$${n_{{N_2}}}:{n_{CO}}::1:2$$
B.
$${n_{{N_2}}}:{n_{CO}}::6:1$$
C.
$${n_{CO}}:{n_{{N_2}}}::1:2$$
D.
$${n_{CO}}:{n_{{N_2}}}::2:3$$
Answer :
$${n_{CO}}:{n_{{N_2}}}::2:3$$
Solution :
Molar ratio of $${N_2}$$ and $$CO$$ is 3 : 2, i.e., $$300\,bar$$
and $$200\,bar,$$ respectively
$$\eqalign{
& \frac{{{n_{{N_2}}}}}{{{n_{CO}}}} = \sqrt {\frac{{{m_{CO}}}}{{m{N_2}}}} \times \frac{{{P_{{N_2}}}}}{{{P_{CO}}}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\, = \frac{{300}}{{200}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\, = \frac{3}{2} \cr} $$