$$2\,k mol$$ of hydrogen at $$NTP$$ expands isobarically to twice its initial volume. The change in its internal energy is ($${C_v} = 10\,kJ/kg.K$$ and atm pressure $$ = 1 \times {10^5}\,N/{m^2}$$ )
A.
$$10.9\,MJ$$
B.
$$9.10\,MJ$$
C.
$$109\,MJ$$
D.
$$1.09\,MJ$$
Answer :
$$10.9\,MJ$$
Solution :
$$\Delta U = n{C_v}\Delta T = 2 \times {10^3} \times 20 \times 273 = 10.9\,MJ.$$
Releted MCQ Question on Heat and Thermodynamics >> Thermodynamics
Releted Question 1
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