$$2\,g$$ of aluminium is treated separately with excess of dilute $${H_2}S{O_4}$$ and excess of $$NaOH.$$ The ratio of the volumes of hydrogen evolved is
A.
2 : 3
B.
1 : 1
C.
2 : 1
D.
1 : 2
Answer :
1 : 1
Solution :
$$\eqalign{
& 2Al + 3{H_2}S{O_4} \to A{l_2}{\left( {S{O_4}} \right)_3} + 3{H_2} \cr
& 2Al + 2NaOH + 2{H_2}O \to 2NaAl{O_2} + 3{H_2} \cr} $$
The ratio of volumes of hydrogen evolved is 1 : 1.
Releted MCQ Question on Inorganic Chemistry >> Hydrogen
Releted Question 1
$$HCl$$ is added to following oxides. Which one would give $${H_2}{O_2}$$ ?