Question
$$20\,g$$ of $$CaC{O_3}$$ on heating gave $$8.8\,g$$ of $$C{O_2}$$ and $$11.2\,g$$ of $$CaO.$$ This is in accordance with
A.
The law of conservation of mass.
B.
The law of constant composition.
C.
The law of reciprocal proportion.
D.
None of these
Answer :
The law of conservation of mass.
Solution :
$$\eqalign{
& CaC{O_3} \to CaO + C{O_2} \cr
& 20\,g\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,8.8\,g\,\,\,\,\,\,\,\,\,11.2\,g \cr} $$
mass of reactant $$ = $$ mass of products $$ = 20g.$$
Hence the law of conservation of mass is obeyed.