Question
2-Bromo-3, 3-dimethylbutane on reaction with aqueous $$KOH$$ yields $$X$$ as the major product. $$X$$ is
A.
2, 3, 3-trimethylpropan-1-ol
B.
2, 2-dimethylbutan-3-ol
C.
2, 3-dimethylbutan-2-ol
D.
2, 2-dimethylpropan-2-ol
Answer :
2, 3-dimethylbutan-2-ol
Solution :
\[\underset{\text{2-Bromo -3, 3-dimethylbutane}}{\mathop{{{H}_{3}}C\underset{\begin{smallmatrix}
| \\
\,\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{CH-}}\,C{{H}_{3}}}}\,\xrightarrow{aq.\,KOH}\] \[\underset{\text{2-3-Dimethylbutan-2-o1}}{\mathop{{{H}_{3}}C-\overset{\begin{smallmatrix}
C{{H}_{3}}\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{CH\,\,-}}\,\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\, \\
OH\,\,\,\,
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,C{{H}_{3}} \\
|\,\,\,\,\,
\end{smallmatrix}}{\mathop{C\,\,-}}}\,C{{H}_{3}}}}\,\]