Question

$$\frac{1}{2}{x^2} + \frac{2}{3}{x^3} + \frac{3}{4}{x^4} + \frac{4}{5}{x^5} + .....{\text{is}}$$

A. $$\frac{x}{{1 + x}} + \log \left( {1 + x} \right)$$
B. $$\frac{x}{{1 - x}} + \log \left( {1 + x} \right)$$
C. $$ - \frac{x}{{1 + x}} + \log \left( {1 + x} \right)$$
D. $$\frac{x}{{1 - x}} + \log \left( {1 - x} \right)$$  
Answer :   $$\frac{x}{{1 - x}} + \log \left( {1 - x} \right)$$
Solution :
$$\eqalign{ & \frac{1}{2}{x^2} + \frac{2}{3}{x^3} + \frac{3}{4}{x^4} + \frac{4}{5}{x^5} + ..... \cr & = \left( {1 - \frac{1}{2}} \right){x^2} + \left( {1 - \frac{1}{3}} \right){x^3} + \left( {1 - \frac{1}{4}} \right){x^4} + \left( {1 - \frac{1}{5}} \right){x^5} + ..... \cr & = \left( {{x^2} + {x^3} + {x^4} + {x^5} + .....} \right) + \left( { - \frac{{{x^2}}}{2} - \frac{{{x^3}}}{3} - \frac{{{x^4}}}{4} - \frac{{{x^5}}}{5}.....} \right) \cr & = \left( {x + {x^2} + {x^3} + .....} \right) + \left( { - \frac{{{x^2}}}{2} - \frac{{{x^3}}}{3} - \frac{{{x^4}}}{4} - \frac{{{x^5}}}{5}.....} \right) \cr & = \frac{x}{{1 - x}} + \log \left( {1 - x} \right) \cr} $$

Releted MCQ Question on
Algebra >> Binomial Theorem

Releted Question 1

Given positive integers $$r > 1, n > 2$$   and that the co - efficient of $${\left( {3r} \right)^{th}}\,{\text{and }}{\left( {r + 2} \right)^{th}}$$    terms in the binomial expansion of $${\left( {1 + x} \right)^{2n}}$$  are equal. Then

A. $$n = 2r$$
B. $$n = 2r + 1$$
C. $$n = 3r$$
D. none of these
Releted Question 2

The co-efficient of $${x^4}$$ in $${\left( {\frac{x}{2} - \frac{3}{{{x^2}}}} \right)^{10}}$$   is

A. $$\frac{{405}}{{256}}$$
B. $$\frac{{504}}{{259}}$$
C. $$\frac{{450}}{{263}}$$
D. none of these
Releted Question 3

The expression $${\left( {x + {{\left( {{x^3} - 1} \right)}^{\frac{1}{2}}}} \right)^5} + {\left( {x - {{\left( {{x^3} - 1} \right)}^{\frac{1}{2}}}} \right)^5}$$       is a polynomial of degree

A. 5
B. 6
C. 7
D. 8
Releted Question 4

If in the expansion of $${\left( {1 + x} \right)^m}{\left( {1 - x} \right)^n},$$    the co-efficients of $$x$$ and $${x^2}$$ are $$3$$ and $$- 6\,$$ respectively, then $$m$$ is

A. 6
B. 9
C. 12
D. 24

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