Question

Electrons are bombarded to excite hydrogen atoms and six spectral lines are observed. If $${E_g}$$ is the ground state energy of hydrogen, the minimum energy the bombarding electrons should posses is

A. $$\frac{{8{E_g}}}{9}$$
B. $$\frac{{15{E_g}}}{16}$$  
C. $$\frac{{35{E_g}}}{36}$$
D. $$\frac{{48{E_g}}}{49}$$
Answer :   $$\frac{{15{E_g}}}{16}$$
Solution :
To obtain 6 spectral line, as electron must be excited to fourth orbit with energy $$\frac{{{E_g}}}{{16}},$$  so that the difference is $$\frac{{15\,{E_g}}}{{16}}.$$

Releted MCQ Question on
Modern Physics >> Atoms And Nuclei

Releted Question 1

If elements with principal quantum number $$n > 4$$  were not allowed in nature, the number of possible elements would be

A. 60
B. 32
C. 4
D. 64
Releted Question 2

Consider the spectral line resulting from the transition $$n = 2 \to n = 1$$    in the atoms and ions given below. The shortest wavelength is produced by

A. Hydrogen atom
B. Deuterium atom
C. Singly ionized Helium
D. Doubly ionised Lithium
Releted Question 3

An energy of $$24.6\,eV$$  is required to remove one of the electrons from a neutral helium atom. The energy in $$\left( {eV} \right)$$  required to remove both the electrons from a neutral helium atom is

A. 38.2
B. 49.2
C. 51.8
D. 79.0
Releted Question 4

As per Bohr model, the minimum energy (in $$eV$$ ) required to remove an electron from the ground state of doubly ionized $$Li$$ atom $$\left( {Z = 3} \right)$$  is

A. 1.51
B. 13.6
C. 40.8
D. 122.4

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